Given that the standard free energy of formation at (298 mathrm{~K}) for (mathrm{NH}_{3}) is (-16.750 mathrm{~kJ} /

Question:

Given that the standard free energy of formation at \(298 \mathrm{~K}\) for \(\mathrm{NH}_{3}\) is \(-16.750 \mathrm{~kJ} / \mathrm{mol}\), the standard Gibbs' free energy change for the ammonia synthesis reaction \(\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}\) (g) \(\rightarrow 2 \mathrm{NH}_{3}(\mathrm{~g})\) is

(a) \(-35.7 \mathrm{~kJ}\)

(b) \(-33.5 \mathrm{~kJ}\)

(c) \(-38.2 \mathrm{~kJ}\)

(d) \(-53.4 \mathrm{~kJ}\).

Fantastic news! We've Found the answer you've been seeking!

Step by Step Answer:

Question Posted: