In Theorem 1.15 prove that (E_{p}(x, delta)=oleft(delta^{p}ight)), as (delta ightarrow 0). Theorem 1.15. Let f be a

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In Theorem 1.15 prove that \(E_{p}(x, \delta)=o\left(\delta^{p}ight)\), as \(\delta ightarrow 0\).

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