Given the concentrations in Practice Problem 14.7, does the equilibrium for the HI reaction lie to the left or to the right? Explain your choice.

Data from Problem 14.7

At the start of the reaction

the concentrations are [H₂] = 0.100 M, [I₂] = 0.100 M, [HI] = 0.000 M. At 427°C, the equilibrium concentrations are [HI] = 0.158 M, [H₂] = 0.021 M, [I₂] = 0.021 M. Calculate K_eq for this reaction.

H(g) + 12(8) 2 HI(g)