Using the energy-level diagram on page 133, calculate the wavelength of the light emitted when the electron
Question:
Using the energy-level diagram on page 133, calculate the wavelength of the light emitted when the electron in a hydrogen atom falls from the n = 5 shell to the n = 3 shell. Report your answer in meters and in nanometers. [1 eV = 1.602 × 10–19 J]
Diagram
Transcribed Image Text:
Relaxation and Emission of Light n = 6 14.2 eV n=5 14.1 eV n = 4 13.8 eV- n = 3 13.1 eV- Energy drop of 1.9 eV- n=2 11.2 eV- n=1 1.0 eV- Increasing energy Energy-level diagram Energy emitted as red light of energy 1.9 eV Vacant shells On=3 n = 2 Bohr diagram
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The energy difference between the n 5 and n 3 shells of a hydrogen atom is ...View the full answer
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Related Book For
Introductory Chemistry Atoms First
ISBN: 9780321927118
5th Edition
Authors: Steve Russo And Michael Silver
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