Question: Using complex numbers, show that sin'0 (35 sin0 - 21 sin 30 + 7 sin 50 sin 70) = = -

Using complex numbers, show that

sin'0 (35 sin 0 - 21 sin 30 + 7 sin 50 sin 70) = = -

sin'0 (35 sin0 - 21 sin 30 + 7 sin 50 sin 70) = = -

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