Question: 1. For a n-vector x, with n = 2m 1 odd, we define the median of x as the scalar value x a such

1. For a n-vector x, with n = 2m – 1 odd, we define the median of x as the scalar value xa such that exactly n of the values in x are ≤ xa and n are ≥ x(i.e., xleaves half of the values in x to its left, and half to its right). Now consider the function f : Rn → R, with values n f(x) = x - | =1 XaExpress f as a scalar product, that is, find a ∈ Rn such that f(x) = aTx for every x. Find a basis for the set of points x such that f (x) = 0.

2. For a ∈ R2, we consider the “power law” function f : R++ → R, with values f (x) = x1α1 x2a2. Justify the statement: “the coefficients αi provide the ratio between the relative error in f to a relative error in xi”.

n f(x) = x - | =1 Xa

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