Question: A 500 g particle has velocity v x = -5.0 m/s at t = -2 s. Force F x = (4 - t 2 )

A 500 g particle has velocity v_x = -5.0 m/s at t = -2 s. Force F_x = (4 - t ²) N, where t is in s, is exerted on the particle between t = -2 s and t = 2 s. This force increases from 0 N at t = -2 s to 4 N at t = 0 s and then back to 0 N at t = 2 s. What is the particle’s velocity at t = 2 s?

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