Given y = (u) and u = g(x), find dy/dx = (g(x))g(x). y = sin u, u
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Given y = ƒ(u) and u = g(x), find dy/dx = ƒ′(g(x))g′(x).
y = sin u, u = 3x + 1
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To solve this problem we can start by finding the derivatives of u and gx u sin ...View the full answer
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Related Book For
Thomas Calculus Early Transcendentals
ISBN: 9780321884077
13th Edition
Authors: Joel R Hass, Christopher E Heil, Maurice D Weir
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