Question: Show that Let S = 1 + 2 + ... + (n - 1) + n S = n + (n - 1) + (n

Show that 

п(п + 1) |1 + 2 +... + (n — 1) + п %3


Let

S = 1 + 2 + ... + (n - 1) + n 

S = n + (n - 1) + (n - 2) + ... + 1 


Add these equations. Then 

25 = [1+ n] + [2 + (n – 1)] + · · · + [n + 1] n terms in brackets

Now, complete the derivation.


( + 1) |1 + 2 +... + (n 1) + %3 25 = [1+ n] + [2 + (n 1)] + + [n + 1] n terms in brackets

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