Show that Let S = 1 + 2 + ... + (n - 1) + n S
Question:
Show that
Let
S = 1 + 2 + ... + (n - 1) + n
S = n + (n - 1) + (n - 2) + ... + 1
Add these equations. Then
Now, complete the derivation.
Transcribed Image Text:
п(п + 1) |1 + 2 +... + (n — 1) + п %3 25 = [1+ n] + [2 + (n – 1)] + · · · + [n + 1] n terms in brackets
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