Given that the impulse response of an ideal integrator over T seconds is h(t) = 1/T [u (t) - u (t - T)] where u(T) is the unit-step function, show that its equivalent noise bandwidth is B_N,idealint = 1 / 2T hertz. You may apply (7.108) using the expression for h(t) directly or find the frequency response function H(f) and then find the equivalent noise bandwidth using (7.106).