The KClO 3 in a 0.1342 g sample of an explosive was determined by reaction with 50.00
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Question:
The KClO 3 in a 0.1342 g sample of an explosive was determined by reaction with 50.00 mL of 0.09601 M Fe 3+ :
ClO 3 - + 6Fe 2+ + 6H + -> Cl - + 3 H 2 O + 6Fe 3+
When the reaction was complete, the excess Fe 2+ was back-titrated with 12.99 mL of 0.08362 M Ce 4+ .
Calculate the percentage of KClO 3 in the sample.
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