1. The first excited state of Ca is reached by absorption of 422.7 nm light. (a) What is the energy difference (kJ/mole) between the ground and the excited state? (b) Knowing that Boltzmann constant = 1.381 x 10-23 J/K and the relative degeneracies are g*/g0 = 3, what is the ratio N*/N0 at 2500 K? (c) (2.5 pt) What will be the ratio N*/N0 at 10,000 K? (d) (2.5 pt) What must be the temperature in order to have a ratio of N*/N0 = 10% of excited atoms?

Answer rating: 100% (QA)

a Energy corresponding to the 4227 nm is the energy differnce ... View the full answer