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The ANOVA summary table for an experiment with five groups, with seven values in each group, is shown to the right. Complete parts (a) through (d) Degrees of Sum of Mean Square below. Source Freedom Squares (Variance) F Among C- 1=4 SSA = 120 MSA = 30 FSTAT = 3.00 groups Within n - c= 30 SSW = 300 MSW = 10 groups Total n - 1 = 34 SST = 420 Click here to view page 1 of the F table. Click here to view page 2 of the F table. Click here to view page 3 of the F table. Click here to view page 4 of the F table. a. At the 0.05 level of significance, state the decision rule for testing the null hypothesis that all five groups have equal population means. Determine the hypotheses. Choose the correct answer below. OA. Ho Hy = H2= . . . = H7 O B. Ho: H1 = H2= . . . =H5 Hy: Hy # H2 # . . . # H7 H1:H, H2 # . . . # 145 O C. Ho: H1 = H2 = . . . = H7 OD. Ho: H1 = H2= . . . = H5 Hy: Not all the means are equal. H,: Not all the means are equal. Find the test statistic. FSTAT = (Round to two decimal places as needed.) Determine the critical value at the 0.05 level of significance Fa =(Round to two decimal places as needed.) b. What is your statistical decision? Ho. There is evidence to conclude that there is a difference in the population means of the groups. Click to select your answer(s) and then click Check Answer. ? All parts showing Clear All Check