12. (0 points) Design a 4-bit arithmetic combinational circuit that performs the following operations: Control Inputs...

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12. (0 points) Design a 4-bit arithmetic combinational circuit that performs the following operations: Control Inputs M₁ Mo 0 0 0 1 1 1 0 1 if(A/4 = = 0) then S = A + B; else S = A - B if(A<B) then S = A + (B * 8); else S = A + (B / 4) S = A + 4 S = A + (B*8) + 1 Operation S(A,B) Both A and B are 4-bit binary unsigned numbers (A3A2A1A0) and (B3B₂B₁B0). M₁, Mo are the control inputs to the arithmetic unit, based on the values of M₁ and Mo the arithmetic unit performs a specific operation. S is the 4-bit output of the arithmetic unit (S3S2S1S0). B*8 is the result of performing integer multiplication of the 4-bit number B by 8 (i.e., multiplying B by 2 three times). A/4 is the result of performing integer division of the 4-bit number A by 4 (i.e., dividing A by 2 twice). → In this question you are required to design the combinational logic circuit inside the arithmetic unit using the minimum number of the following components: invertors, 4-bit Comparator, 4-bit adders, and 4:1 Multiplexers. You are not allowed to use any other logic components. use 2's complement arithmetic within the design of your circuit once needed. ❖ Clearly mark the pins of any component you use by identifying its inputs, outputs, and controls, and explain your solution (No credit without fully explaining the circuit). ❖ Hint: multiplication by 2 and division by 2 can be performed by shifting left and shifting right, respectively. 12. (0 points) Design a 4-bit arithmetic combinational circuit that performs the following operations: Control Inputs M₁ Mo 0 0 0 1 1 1 0 1 if(A/4 = = 0) then S = A + B; else S = A - B if(A<B) then S = A + (B * 8); else S = A + (B / 4) S = A + 4 S = A + (B*8) + 1 Operation S(A,B) Both A and B are 4-bit binary unsigned numbers (A3A2A1A0) and (B3B₂B₁B0). M₁, Mo are the control inputs to the arithmetic unit, based on the values of M₁ and Mo the arithmetic unit performs a specific operation. S is the 4-bit output of the arithmetic unit (S3S2S1S0). B*8 is the result of performing integer multiplication of the 4-bit number B by 8 (i.e., multiplying B by 2 three times). A/4 is the result of performing integer division of the 4-bit number A by 4 (i.e., dividing A by 2 twice). → In this question you are required to design the combinational logic circuit inside the arithmetic unit using the minimum number of the following components: invertors, 4-bit Comparator, 4-bit adders, and 4:1 Multiplexers. You are not allowed to use any other logic components. use 2's complement arithmetic within the design of your circuit once needed. ❖ Clearly mark the pins of any component you use by identifying its inputs, outputs, and controls, and explain your solution (No credit without fully explaining the circuit). ❖ Hint: multiplication by 2 and division by 2 can be performed by shifting left and shifting right, respectively.

Answer rating: 100% (QA)

To design the 4bit arithmetic combinational circuit we can break down the problem into smaller components Lets start by designing the individual components required for the circuit 1 4bit Comparator W... View the full answer