13. Assuming the experiment was executed without error, 1b. Use the starting amount of Mg,0.386g. and the result from determine the mass of MgO produced from 0.386g of Mg by the part (1a) to determine the mass percent of Mg in MgO. Enter reaction: 2Mg(5)+O2(g)2MgO(s) using that 1.6583g of the result in percent to the nearest 0.01%. Do not enter the % MgO is formed from 1.0000gMg. Enter the result in g to the symbol. nearest 0.001.9. Do not enter the unit. In the experiment, water is added to convert the small amount of magnesium nitride (Mga N2 ) that might have been produced during magnesium combustion into magnesium oxide (MgO). Part 2 will explore the consequences of skipping this step. Consider the same 0.386g of magnesium (Mg) being heated in a crucible under combustion conditions where 89.71% of the magnesium is converted inte magnesium oxide (MgO) and 10.29% of the magnesium is converted into magnesium nitride (Mg3 N2 ). Answer the following questions assuming the procedural error of not adding water to convert magnesium nitride to magnepium oxide. 2a. Determine the mass of MgO produced by the reaction: 2 2b. Determine the mass of Mg3N2 produced by the reaction: 3 Mg(s)+O2(g)2MgO(s) using that 1.6563g of MgO is formed Mg(s)+N2(g)Mg3N2(s) using that 1.3842g of MgN2 is rom 1.0000gMg. Remember that only 89.71% of the Mg formed from 1.0000gMg. Remember that only 10.29% of the produces MgO. Enter the result in g to the nearest 0.001g. Do Mg produces MgaN2. Enter the result in g to the nearest 0.001. not enter the unit. 9. Do not enter the unit. 20. II the procedural mistake was not recognized and the experimental resuls were analyzed as if the mass of all solid products MgO(s) and Mg2N2(s)) was pure MgOO, what mass percent of Mg in MgO would be determined? Enter the result to the noarest 0.01%. Do not enter the % symbol. 3. Select the words which correcty summarizes the result of the procedural error. HiNT: Compare the answers to part 1 and part 2c. The determine mass percent of Mg in MgO is in MeO