1a. Assuming the experiment was executed without error, 16. Use the staiting amount of Mg0.0.392g, and the result from determine the mass of MgO produced from 0.392g of Mg by the part (1a) to determine the mass percent of Mg in MgO. Enter reaction: 2Mg(5)+O2(g)2MgO(5) using that 1.6583g of the resalt in percent to the nearest 0.01%. Do not enter the \% MgO is formed from 1.0000gMg Enter the result in g to the symbol, nearest 0.001g. Do not enter the unit. In the experiment, water is added to convert the smal amount of magnesium nhide (Mg2N2) that might have been produced during magnesium combustion into magnesium oxide (MgO). Pat 2 will explore the consequences of skipping this step Consider the same 0.392g of magnesium (MO0 being beated in a crucible under combustion conditions where 90.25% of the magnesian is converted into magnessum oxde (MgO) and 9.75% of the magnesium L converted into magnesium nitrude (MgN2). Arswer the following questions assuming the procodurat error of not adding water to convert magngsium nitride to magnesium oxide. The Cotermine mass perceot of Mo in Mgo of