16&17

The credit union is now considering adding a third teller (in the form of an M/M/3) with the goal of solving the following argument: arg min $15s +$11E [L] 8E (23) Recall the term "arg min" or "argument of the minima" gives the solution s such that the function f(s) = $15s +$11EL,) attains its minimum value. Before solving this problem, what is the utilization p for s = 3? (Hint: remember that I and I were given in the opening scenario.) S O a. 0.4 b. 0.67 O c. 0.33 Od 0.5 17 Using your answer to the above question, what is the average number in the queue EL] for S = 3? S ut of a. 1.02 customers b. 2.03 customers C 0.07 customers d. 0.85 customers