Question: 2. A small object (m = 0.020 kg) is hanging (vertical) from an ideal spring and per- forming simple harmonic motion. At t =
2. A small object (m = 0.020 kg) is hanging (vertical) from an ideal spring and per- forming simple harmonic motion. At t = 0 s, the mass is located at 0.19 m above the equilibrium position. Its velocity at that point is 0.37m/s upwards while its ac- celeration has a value of 1.42 m/s2 downwards. (a) Find the function of the general form x = A cos wt + 0) that describes this mo- tion For the location of the mass (treat the x-axis as being positive downwards) (b) What is the total energy of the system at t = 2.0 s?
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
