Question: 2 Fe( s ) + 3 / 2 O 2 ( g ) Fe 2 O 3 ( s ) H = -823 kJ 3

2 Fe(s) + 3/2 O2(g) Fe2O3(s) H = -823 kJ
3 Fe(s) + 2 O2(g) Fe3O4(s) H = -1120. kJ

Calculate the H for the following reaction.

3 Fe2O3(s) 2 Fe3O4(s) + O2(g)

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