$2$ HI$($aq$)+$ K$2$CO$3($aq$)->$ H$2$O$($l$)+$ CO$2($g$)+2$ KI$($aq$)$

For this reaction, how many moles of CO$2$ are formed from the reaction of $1\mathrm{.}6$ mol HI with $0\mathrm{.}94$ mol K$2$CO$3?$