2: The given example in the image I uploaded should be the format of the solution:

Example 4: Solve for compound amount and compound interest at the end of 2 years if P 10,000 is nvested at 6% compounded semiannually. Given: P = 10, 000 r= .06 m = 2 t= 2 yrs. Solution: 1=1 9.06 - = 0.03 n = txm = 2x2 = 4 F = P(1 + ()" = 10000(1 +.03)* = P11,255.09 (Compound amount) 1 = F - P = 11,255.09 - 10000 = P1,255.09 (Compound Interest) Finding Time and Rate Time refers to the term of an investment or how long it will take a certain sum of money to amount to a certain other sum if it is invested at a certain interest rate The logarithmic method is used to find n when the interest rate is compounded log (F + P) log (1+ 1) When the amount, present value and the time are given, interest rate or periodic rate can be determined using scientific calculator. i = VF +P- 1 r = (m) (1) Example 5: How many years will P100, 000 earned a compound interest of P50, 000 if the interest rate is 9% compounded quarterly. Given: P =100,000 1 = 50,000 = 9% or .09 m = 4 Solution: F = P + / = 100,000 + 50,000 = P150,000 leg (F+P) _lag(156.060-100.090) = 18.22 log (1+ 0225) 1=4- 14 = 4.56 years Example 6: Find the rate compounded quarterly if P17, 345.00 accumulates to P22, 325 in 3 years and 5 months. Given: P = 17,345 F = 22,325 t= 3-5 or #years m = 4 Solution: n = txm = $1x4 = 4yrs 1= VF +P- 1= V22325 + 17345- 1 =.01864 r = (m)(1) = 4x.01864 =.07456 = 7.456% Solve: 1. Find the compound amount and interest on P107, 400 for 5 years at 5% compounded semi-annually. 2. Find the value of the following if the present value is P7,000 at 6%: a. Compounded annually for 55 years b. Compounded semi-annually for 42 years Compounded quarterly for 35 years Compounded monthly for 21 years