24. The club of the preceding exercise has two members named Jack and Jill. They have...

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24. The club of the preceding exercise has two members named Jack and Jill. They have calculated that 2,380 of the committees have Jack on them, 2,380 have Jill, 1,820 have Jack but not Jill, 1,820 have Jill but not Jack, and 560 have both Jack and Jill. (a) How many committees have either Jack or Jill? Here is an algorithm for Exercise 24(a): "There are 2,380 committees that have Jack, and 2,380 that have Jill. By the sum rule, there are 2,380 +2,380 = 4,760 that have either Jack or Jill." Explain the error, and correct the algorithm. 24. The club of the preceding exercise has two members named Jack and Jill. They have calculated that 2,380 of the committees have Jack on them, 2,380 have Jill, 1,820 have Jack but not Jill, 1,820 have Jill but not Jack, and 560 have both Jack and Jill. (a) How many committees have either Jack or Jill? Here is an algorithm for Exercise 24(a): "There are 2,380 committees that have Jack, and 2,380 that have Jill. By the sum rule, there are 2,380 +2,380 = 4,760 that have either Jack or Jill." Explain the error, and correct the algorithm.