3. A 4 to 2 priority encoder has four inputs Y3,Y2,Y1 \& Y0 and two outputs A1 \& A0. The input Y3 has the highest priority, whereas the input, Y0 has the lowest priority. In this case, even if more than one input is ' 1 ' at the same time, the output will be the binary code corresponding to the input, which is having higher priority. (25 pts) We will consider one more output, V in order to know, whether the code available at outputs is valid or not. - If at least one input of the encoder is ' 1 ', then the code available at outputs is a valid one. In this case, the output, V will be equal to 1 . - If all the inputs of encoder are ' 0 ', then the code available at outputs is not a valid one. In this case, the output, V will be equal to 0 A. Generate the truth table. B. Using K-map or Boolean algebra, determine the logical expression for outputs. C. Draw the circuit diagram of the outputs in step b