Question: 32-bit addresses, byte addressing 256-byte pages A page table entry occupies 4 bytes For 1-level paging, if only the lowest 4,096 and highest 4,096 addresses

32-bit addresses, byte addressing

256-byte pages

A page table entry occupies 4 bytes

For 1-level paging, if only the lowest 4,096 and highest 4,096 addresses are in use, how many page tables are needed and how much memory is occupied by page tables? (Recall that 4,096 equals 2^12 )

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