Question: { 4 mark } Now assume that speeding up the floating - point unit slowed down data cache accesses, resulting in a 1 . 5

{4 mark} Now assume that speeding up the floating-point unit slowed down data cache accesses, resulting in a 1.5\times slowdown (or 2
3
speedup). Data cache accesses consume 10% of the original execution
time. What is the overall speedup now?

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