Question: 5. Define h(x) = x' sin , for x # 0 and h(0) = 0. Show that h is differentiable everywhere and that h' is

5. Define h(x) = x' sin , for x # 0 and h(0) = 0. Show that h is differentiable everywhere and that h' is continuous everywhere but fails to have a derivative at one point. You may use the rules for differentiating products, sums, and quotients of elementary functions that you learned in calculus

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