6.

To evaluate the given function, it should become 3 points sinu du None of the above 2 sin u cos u du Oo OK (1 -cos u) du (1 + cos 2u ) du OH OM /7(1 - cos 21) du OPEvaluate 3 points -4x2 +8x dx V7-3x2 + x3 -2 None of the above + C (7-3x2 + x3 ) OP OH -4 + C 30/ ( 7 - 3 x2 + x3 ) 3 V (7- 3x2 + x3 ) +0 Oo OM -2 1/ (7 - 3x2 + x3 ) 2 + C OKEvaluate 3 points /4* ( 32 *+1 ) dx 32 (27x ) 22x+5 + C + C In 2 In 128 OP OM (27x ) + C None of the above In 128 Oo OH 27x+5 + C In 2 OK\fIn using integration by parts, you have to divide the given integrands into 3 points 5 parts 2 parts OP OM 4 parts 3 parts Oo OK None of the above OH