Question: A c chart is plotted based on count of nonconformities for 1000 accounting transactions per day from December to January. The sum of c=369 with





A c chart is plotted based on count of nonconformities for 1000 accounting transactions per day from December to January. The sum of c=369 with subgroups of 26. One of the subgroups with c = 38 is out-of-control. What is the CO for February? O 14.19 2.89 O 25.49 O 13 24 The specification for an electronic device is 3 + 0.10 amps. Given that the oo = 0.02. Which of the following statement is WRONG? * I. The process is capable of producing within specification. The Cp value is 1.67. The Cpk value is 5.00. The process is not capable of producing within specification. IV. III and IV O II and IV I and II I and III ottling machines A, B and Care evaluated for their capability. The d deviations of the three machines are 0.05, 0.10 and 0.20, respective -cifications are set between 15.8 and 16.2. Based on the Cp value, whic es are capable of producing within specifications?* Chine A Chine C ne of the above Chine B charts for X-bar and Rare plotted based on the critical dimension of cturing process. Subgroup size is 5 with subgroups of 25. The sum of 2.5 mm and sum of R= 90.0 mm. Calculate the value of o on the tion that the process was in state of statistical control. o 5 50 Control charts of X-bar and s are established on the Brinell hardness of a steel. The data collected are shown in Table 1. The subgroup size is 8. How do you comment on the process? W 24 29 26 28 23 Table 1: Data measured in kilograms per square millimeter. Subgroup Number S Subgroup Number 1 540 26 2 534 23 15 545 24 16 561 27 5 576 25 18 6 523 50 7 571 29 8 547 9 584 10 552 24 541 28 12 545 25 13 546 551 522 579 549 508 569 574 563 561 548 556 28 a & Cia 24 23 26 O The process is out-of-control. . There 2 outliers found outside the control limits The process is statistical stable and in control. No comment. Ap-chart is established on a painting process. 35 pieces are inspected every 4 hours and the fraction nonconforming is 0.06. Calculate the central line. * O 0.18 2.10 0 8.75
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