A copper valve is used in the waste exit line from a pharmaceutical process reactor which...

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A copper valve is used in the waste exit line from a pharmaceutical process reactor which is producing iodine-containing organics. The waste stream is composed of air saturated 15% sulfuric acid with the following impurities: ferric sulfate, ferrous sulfate, potassium iodide, and iodine. From the electrochemical data listed below, determine the corrosion potential and corrosion rate in this brew. Assume all Tafel constants are 0.1 V; Cu = Cu+² + 2e; E = -0.350 V; io = 10-4 A/cm² H2 = 2H+ + 2e; E = 0.020 V; io 2x 107 A/cm² (on Cu), | = İLim (H+ >> H2) = 2 x 10-1 A/cm²; ILim (H2 > H+) = 104 A/cm². Fe+2 = Fee E=0.850 V; io 8 x 10-5 A/cm² (on Cu). = İLim (Fe+3 Fe+2) = 6 x 103 A/cm², İLim (Fe+2-> Fe+3) = 2 x 104 A/cm². 12+2e 21: E = 0.430 V; io = 103 A/cm² (on Cu), ILim (12) = 2 x 10-3 A/cm². İLim (12) 2 x 10-2 A/cm². A copper valve is used in the waste exit line from a pharmaceutical process reactor which is producing iodine-containing organics. The waste stream is composed of air saturated 15% sulfuric acid with the following impurities: ferric sulfate, ferrous sulfate, potassium iodide, and iodine. From the electrochemical data listed below, determine the corrosion potential and corrosion rate in this brew. Assume all Tafel constants are 0.1 V; Cu = Cu+² + 2e; E = -0.350 V; io = 10-4 A/cm² H2 = 2H+ + 2e; E = 0.020 V; io 2x 107 A/cm² (on Cu), | = İLim (H+ >> H2) = 2 x 10-1 A/cm²; ILim (H2 > H+) = 104 A/cm². Fe+2 = Fee E=0.850 V; io 8 x 10-5 A/cm² (on Cu). = İLim (Fe+3 Fe+2) = 6 x 103 A/cm², İLim (Fe+2-> Fe+3) = 2 x 104 A/cm². 12+2e 21: E = 0.430 V; io = 103 A/cm² (on Cu), ILim (12) = 2 x 10-3 A/cm². İLim (12) 2 x 10-2 A/cm².

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012 Reaction cut the given Tafel const 01v where E 0350 V J 104 Acm on c... View the full answer