$($a$)$ Energy is required to separate a nucleus into its constituent nucleons, as the drawing indicates; this energy is the total binding energy of the nucleus. In a similar way one can speak of the energy that binds a single nucleon to the remainder of the nucleus. Fo example, separating nitrogen $7$N $^15$ into $7$N $^14$ and a neutron takes energy equal to the binding energy of the neutron. Find the ener $($in MeV$)$ that binds the neutron to the $7$N $^15$ nucleus by considering the mass of $7$ N $^14($atomic mass $=14\mathrm{.}003074$u $)$ and the mass of o $*$ n $^1$ atomic mass $=1\mathrm{.}008665$u $),$ as compared to the mass of $7^($N $^15)($atomic mass $=15\mathrm{.}000108$u $)($b$)$ Similarly, one can speak of the energy that binds a single proton to the $7$N $^15$ nucleus. Following the procedure outlined in part $($a$),$ determine the energy $($in MeV$)$ that binds the proton $($atomic mass $=1\mathrm{.}007825$u $)$ to the $7^($N $^15)$ nucleus. The atomic mass of carbon $6$C $^14$ is $14\mathrm{.}003242$ u$.($c$)$ Which nucleon is more tightly bound, the neutron or the proton?