A explosion breaks a $23\mathrm{.}0-$kg object into three parts. Part $(1)$ has a mass m$1=4\mathrm{.}90-$kg and a velocity of $50\mathrm{.}0$ m$/$s due east.Part $(2)$ has a mass m$2=4\mathrm{.}30-$kg and a velocity of $74\mathrm{.}0$ m$/$s due north.what is the magnitude of velocity of part $3$

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To find the magnitude of the velocity of part 3 we can use the principle of conservation of momentum ... View the full answer