Question: A material (which is a lot like lead) melts at 327 C. Its latent heat of fusion is 6 cal g, its density is

A material (which is a lot like lead) melts at 327 C. Its latent heat of fusion is 6 cal g, its density is 10 g cm, its molecular weight is 200, and its atomic dia- meter is 3 A. What is the entropy of melting in units of R (= 1.98 cal/mol deg)? Assuming that the surface free energy is given by Turnbull's rule (o = aL/2), what is o in ergs cm2? Sketch the free energy as a function of radius for a spherical cluster of the solid in the liquid at 227 C. Sketch the nucleation rate as a function of temperature, using 1 = 5 x 1022 exp(-AF*/kT), where I is the nucleation rate, AF* is the free energy of a cluster of critical size, and k = 1.381 x 10-6 ergs/C.

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To find the entropy of melting we can use the formula S H T where S is the entropy of melting H is the enthalpy of fusion and T is the temperature at ... View full answer

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