Question: A simple diode rectifier is shown in Fig. 1. The diode is assumed to be ideal. The supply voltage is v(t) = SQUAREROOT2 times 230

A simple diode rectifier is shown in Fig. 1. The diode is assumed to be ideal. The supply voltage is v(t) = SQUAREROOT2 times 230 times sin wt V, where omega = 2pi50 rad/s. Sketch the supply voltage v^s(t), the load voltage v_d(t) and the circuit current i(t). Sketch the voltage across the diode v_D(t). Calculate the average voltage across the load V_d. Calculate the power delivered to the load.

7. A simple diode rectifier is shown in Fig. 1. The diode

7. A simple diode rectifier is shown in Fig. 1. The diode is assumed to be ideal. The supply voltage is v(1)=2x230xsin at V, where = 2750 rad/s. i(t) v(t) VD(1) va(1) 10 Fig. 1 (a) Sketch the supply voltage v(1), the load voltage va(t) and the circuit current i(t). (b) Sketch the voltage across the diode vp(1). (c) Calculate the average voltage across the load V (d) Calculate the power delivered to the load.

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