A stage extraction process is depicted in Fig. P9.13. In such systems, a stream containing a weight fraction yin of a chemical enters from the left at a mass flow rate of F1. Simultaneously, a solvent carrying a weight fraction xin of the same chemical enters from the right at a flow rate of F2 Thus, for stage i, a mass balance can be represented as F19-1+F2X1+1 = F19 + F22 (P9.13a) At each stage, an equilibrium is assumed to be established between yi and xi as in K= (P9.135) where Kis called a distribution coefficient. Equation (P9.135) can be solved for xi and substituted into Eq (P9.13a) to yield --(1+x) x + (x ) x+1 = 0 (P9.130) If F1 = 400 kg/h, yin = 0.1, F2 = 800 kg/h, xin = 0, and K = 5, determine the values of you and out if a five-stage reactor is used. Note that Eq (P9.13c) must be modified to account for the inflow weight fractions when applied to the first and last stages. -Flow - 2