acid base titration lab

$\backslash$table$[[$acid$,$trial $1,$I trial $1,$trial $3,$trial $4],[$molarify of standard acid,$0\mathrm{.}1021m,],[$Initial reading of acid buret,$0\mathrm{.}00L,28\mathrm{.}10mL,44\mathrm{.}00mL,],[$Final reading of acid buret,$28\mathrm{.}10mL,44\mathrm{.}00mL,50\mathrm{.}00mL,],[$volume of acid added,$28\mathrm{.}10mL,15\mathrm{.}9mL,6mL,],[$base darr,,,,$],[$inithal reading of base buret,$0\mathrm{.}00L,29\mathrm{.}30mL,30\mathrm{.}00mL,],[$final reading of base buret,$29\mathrm{.}30mL,30\mathrm{.}00mL,50\mathrm{.}00mL,],[$volume of base added,$29\mathrm{.}30mL,0\mathrm{.}7mL,20mL,]]$

trial $1$darr

Volumeacid convert to $L$ use Macid cor ert to

find molarity of NaOH solution $p\mathrm{.}2$

trial $2vv$

volumeacid convert to use Macid convert to mole base molNaOH

$[\frac{0\mathrm{.}0016}{15\mathrm{.}90(mL)\text{s}\text{o}\text{r}\text{u}\text{t}\text{i}\text{o}\text{n}}][\frac{1000(mL)}{1(L)}]=\left[\begin{array}{c}0\mathrm{.}1006M\\ \text{N}\text{a}\text{O}\text{H}\end{array}\right]$

moi NaOH

trial $3$

$u$

rolumeacid convert toL use Macid convert to mote mol NaOH

$6\mathrm{.}00mL$

Find molaraty of NaOH Solution $(P-2)$

$0\mathrm{.}0006$

mol NaOH