Question: acid base titration lab table [ [ acid , trial 1 , I trial 1 , trial 3 , trial 4 ] , [

acid base titration lab
\table[[acid,trial 1,I trial 1,trial 3,trial 4],[molarify of standard acid,0.1021m,],[Initial reading of acid buret,0.00L,28.10mL,44.00mL,],[Final reading of acid buret,28.10mL,44.00mL,50.00mL,],[volume of acid added,28.10mL,15.9mL,6mL,],[base darr,,,,],[inithal reading of base buret,0.00L,29.30mL,30.00mL,],[final reading of base buret,29.30mL,30.00mL,50.00mL,],[volume of base added,29.30mL,0.7mL,20mL,]]
trial 1darr
Volumeacid convert to L use Macid cor ert to
mol NaOH
28.10mL
find molarity of NaOH Solution p.2
trial 2darr
volumeacid convertiol use Macid convert to mol NaOH
15.90mL
find malarity of NaOH solution (1.2) MNaOH
% difference (show calculations)
between trial land 2/ between thal 2 and 3|between trials 1 and 3
%=molarityA-BmolarityB100,??%molarityA-BmolarityB100
%molarityA-BmolarityB100
MOI NaOH~~
0.0034molNaO
=0.0016 man
trial 3darr
rolumeacis convert toL usemacid canvert to mole mol NaOH
Find molahty of NaOH Salution (p.2)
0.0006
molNaOH
 acid base titration lab \table[[acid,trial 1,I trial 1,trial 3,trial 4],[molarify of

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