Question: Activity ES EF A B C D E F G H Activity LS LF A B C D E F G H Activity Slack A


| Activity | ES | EF |
| A | ||
| B | ||
| C | ||
| D | ||
| E | ||
| F | ||
| G | ||
| H |
| Activity | LS | LF |
| A | ||
| B | ||
| C | ||
| D | ||
| E | ||
| F | ||
| G | ||
| H |
| Activity | Slack |
| A | |
| B | |
| C | |
| D | |
| E | |
| F | |
| G | |
| H |
The total project completion time corresponds to the longest path in the network. The total project completion time for Dave?
Time (weeks) Time (weeks) Immediate Predecessor(s) Activity 7 - E Activity A B D 6 - Immediate Predecessor(s) 4 B 5 B 10 C, E 6 DF 4 A 1A (Ctr Dave Fletcher was able to determine the activity times for constructing his laser scanning machine. Fletcher would like to determine ES, EF, LS, LF, and slack for each activity. The total project completion time and the critical path should also be determined. Here are the activity times: Immediate Predecessor(s) Time Activity (weeks) A 7 B 6 4 D 1 Time Activity (weeks) E 4 F 5 G 10 H 6 Immediate Predecessor(s) B B C, E D. A Dave's earliest start (ES) and earliest finish (EF) are: ES EF Activity AStep by Step Solution
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