An electrochemical cell is based on these two half$-$reactions and their given standard reduction potential values:

Ox: $Sn(s)S{n}^{2+}(aq,1\mathrm{.}70(mol)L^{-1})+2e^{-},E_{\text{a}\text{n}\text{o}\text{d}\text{e}}=-0\mathrm{.}14(V)$

Red: bar