An electron $($mass $=9\mathrm{.}11$x$10-31$ kg; charge $=1\mathrm{.}602$x$10-19$ C$)$ is placed at the negative terminal of a parallel plate capacitor with a separation of $0\mathrm{.}013$ m$.$ Once activated, an electric field of $2,874$ N C$-1$ accelerates the electron towards the positive terminal. Find the magnitude of the kinetic energy of the particle when it hits the positive plate.

Give your answer in electron volts $($eV$)$ noting that $1$ eV $=1\mathrm{.}602$x$10-19$ J$.$