Question: Analyze the following code: What is the time complexity? int fun(int n) { int count = 0; for (int i = n; i >
Analyze the following code: What is the time complexity? int fun(int n) { int count = 0; for (int i = n; i > 0; i /= 2) for (int j=0; j
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The time complexity of the given code is On log n The outer loop runs logn times ... View full answer
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