Question: Assume that a dictionary variable has been initialized with the inventory of a supermarket (with the rest of the items typed out): inventory =

Assume that a dictionary variable has been initialized with the inventory of a supermarket (with the rest of

Assume that a dictionary variable has been initialized with the inventory of a supermarket (with the rest of the items typed out): inventory = { "Apples": 50, "Bananas": 35, "Cauliflower": 0,..., "Zucchini": 72} The following algorithms all attempt to perform the same task of checking how many "Zucchini" will be in stock. Which of the correct algorithms do you expect to be the fastest? Group of answer choices print (inventory == "Zucchini") for item, quantity in inventory: if item == "Zucchini": print (quantity) print(inventory/"Zucchini"]) for item in inventory: if item == "Zucchini": print(inventory/item/)

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