At a certain temperature, the equilibrium constant $K$ for the following reaction is $0\mathrm{.}0049$ :

$B{r}_2(g)+OC{l}_2(g)BrOCl(g)+BrCl(g)$

Use this information to complete the following table.

Suppose a $47.$ L reaction vessel is filled with $0\mathrm{.}82$mol of BrOCl and $0\mathrm{.}82$mol of $BrCl.$ What can you say about the composition of the mixture in the vessel at equilibrium?

What is the equilibrium constant for the following reaction?

Round your answer to $2$ significant digits.

$BrOC{l}_{(g)}+BrC{l}_{(g)}B{r}_2(g)+OC{l}_2(g)$

What is the equilibrium constant for the following reaction?

Round your answer to $2$ significant digits.

$3B{r}_2(g)+3OC{l}_2(g)3BrOC{l}_{(g)}+3BrC{l}_{(g)}$

There will be very little $B{r}_2$ and $OC{l}_2.$

There will be very little BrOCl and $BrCl.$

Neither of the above is true.

$K=$

$K=$