Question: At a certain temperature, the equilibrium constant K for the following reaction is 0.0037: CO(g) + H2O(g) + CO2(g) + H2 (8) Use this information

At a certain temperature, the equilibrium constant K for the following reaction is 0.0037: CO(g) + H2O(g) + CO2(g) + H2 (8) Use this information to complete the following table. There will be very little co and H20. Suppose a 6.0 L reaction vessel is filled with 0.51 mol of CO and 0.61 mol of H20. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little co, and H2. Neither of the above is true. What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. K = 0 K = CO2(0)+H2() CO(g)+H, O(9) What is the equilibrium constant for the following reaction? Round your answer to 2 significant digits. K = 0 = 3 CO(9)+3H (9) 3 CO2(0)+3H (9)
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