A 4.0 kg block initially at rest is pulled to the right along a horizontal surface...
Fantastic news! We've Found the answer you've been seeking!
Question:
Transcribed Image Text:
A 4.0 kg block initially at rest is pulled to the right along a horizontal surface by a constant horizontal force of 13 N. (a) A block pulled to the right on a rough surface (b) The applied force is at an angle 8 to the by a constant horizontal force. horizontal. mg mg a (For the following, when entering a mathematical expression, do not substitute numerical values; use variables only.) (a) Find the speed of the block after it has moved 2.5 m if the surfaces in contact have a coefficient of kinetic friction of 0.14. SOLUTION Conceptualize This example is similar to the example "A Block Pulled on a Frictionless Surface" in Chapter 7, but modified so that the surface is no longer frictionless. The rough surface applies a friction force on the block opposite to the applied force. As a result, we expect the speed to be -Select-- v that found in "A Block Pulled on a Frictionless Surface." Categorize The block is pulled by a force and the surface is rough, so the block and the surface are modeled as --Select- v system with a nonconservative force. Analyze Figure (a) illustrates this situation. Neither the normal force nor the gravitational force does work on the system because their points of application are displaced horizontally. Find the work done on the system by the applied force (Use the following as necessary: F and Ax.): > Wother forces = WE = Apply the particle in equilibrium model to the block in the vertical direction (Use the following as necessary: F, Ax, m, and g.): >Fy = 0 + n- mg = 0 -n = Find the magnitude of the friction force (in N): N = buri = ưn = ! Substitute the energies into the equation shown and solve for the final speed of the block (Use the following as necessary: F, Ax and f): FAx = AK + AEint = Gmv? - 0) + fAx FAx = AK + ΔΕint = (mv-0) + fAAx V = Substitute numerical values (Enter your answer in m/s.): m/s Finalize As expected, this value is ---Select-- v that found in the case of the block sliding on a frictionless surface. The difference in kinetic energies between the block sliding on a frictionless surface and the block in this example is equal to the increase in internal energy of the block-surface system in this example. (b) Suppose the force F is applied at an angle 8 as shown in figure (b). At what angle should the force be applied to achieve the largest possible speed after the block has moved 2.5 m to the right? SOLUTION Conceptualize You might guess that 0 = 0 would give the largest speed because the force would have the largest component possible in the direction parallel to the surface. Think about F applied at an arbitrary nonzero angle, however. Although the horizontal component of the force would be reduced, the vertical component of the force would -Select- v the normal force, in turn reducing the force of friction, which suggests that the speed could be maximized by pulling at an angle other than 8 = 0. Categorize As in part (a), we model the block and the surface as a nonisolated system with a --Select-- v force acting. Analyze Find the work done by the applied force, noting that d = Ax because the path followed by the block is a straight line (Use the following as necessary: F, Ax, and 0.): (1) 2Wother forces = WE = Fd cos(0) = Apply the particle in equilibrium model to the block in the vertical direction: SF, = n + F sin(6) - mg = o Solve for n (Use the following as necessary: F, Ax, 0, m and g.): (2) n = Use ) Wather forces = W = AK + AEt to find the final kinetic energy for this situation: WE = AK + AEint = (K; - 0) + fAx - K; = WF - fAx Substitute the results in Equations (1) and (2): K; = FAx cos(0) - HnAx = FAx cos(e) – H(mg - F sin(8))Ax Maximizing the speed is equivalent to maximizing the final kinetic energy. Consequently, differentiate K; with respect to 6 and set the result equal to zero (Use the following as necessary: Ax, 0, and g.): = -FAx sin(0) - H(0 - F cos(0))Ax = 0 de -sin(8) + u, cos(0) = 0 Evaluate 6 (in degrees) for u, = 0.14: 0.12 DAA = Hk Evaluate e (in degrees) for 4 = 0.14: e = tan-(u,) = tan-(0.14) = Finalize Notice that the angle at which the speed of the block is a maximum is indeed not 8 = 0. When the angle exceeds 7.97°, the horizontal component of the applied force is too small to be compensated by the reduced friction force and the speed of the block begins to --Select-- v from its maximum value. EXERCISE A 17.5 kg block is dragged over a rough, horizontal surface by a 75 N force acting at 21° above the horizontal. The block is displaced 5.7 m, and the coefficient of kinetic friction is 0.150. (Enter your answers in J.) Hint (a) Find the work done on the block by the 75 N force. (b) Find the work done on the block by the normal force. (c) Find the work done on the block by the gravitational force. (d) What is the increase in internal energy of the block-surface system due to friction? (e) Find the total change in the block's kinetic energy. Need Help? Read It 2. [3.12/3.12 Points] DETAILS PREVIOUS ANSWERS SERPSE10 8.XP.005. MY NOTES ASK YOUR TEACHER An object of mass m starts from rest and slides a distance d down a frictionless incline of angle 0. While sliding, it contacts an unstressed spring of negligible mass as shown in the figure. The object slides an additional distance x as it is brought momentarily to rest by compression of the spring (of force constant k). Find the initial separation d between object and spring. (Use any variable or symbol stated above along with the following as necessary: g.) d = 2mg sin (e) A 4.0 kg block initially at rest is pulled to the right along a horizontal surface by a constant horizontal force of 13 N. (a) A block pulled to the right on a rough surface (b) The applied force is at an angle 8 to the by a constant horizontal force. horizontal. mg mg a (For the following, when entering a mathematical expression, do not substitute numerical values; use variables only.) (a) Find the speed of the block after it has moved 2.5 m if the surfaces in contact have a coefficient of kinetic friction of 0.14. SOLUTION Conceptualize This example is similar to the example "A Block Pulled on a Frictionless Surface" in Chapter 7, but modified so that the surface is no longer frictionless. The rough surface applies a friction force on the block opposite to the applied force. As a result, we expect the speed to be -Select-- v that found in "A Block Pulled on a Frictionless Surface." Categorize The block is pulled by a force and the surface is rough, so the block and the surface are modeled as --Select- v system with a nonconservative force. Analyze Figure (a) illustrates this situation. Neither the normal force nor the gravitational force does work on the system because their points of application are displaced horizontally. Find the work done on the system by the applied force (Use the following as necessary: F and Ax.): > Wother forces = WE = Apply the particle in equilibrium model to the block in the vertical direction (Use the following as necessary: F, Ax, m, and g.): >Fy = 0 + n- mg = 0 -n = Find the magnitude of the friction force (in N): N = buri = ưn = ! Substitute the energies into the equation shown and solve for the final speed of the block (Use the following as necessary: F, Ax and f): FAx = AK + AEint = Gmv? - 0) + fAx FAx = AK + ΔΕint = (mv-0) + fAAx V = Substitute numerical values (Enter your answer in m/s.): m/s Finalize As expected, this value is ---Select-- v that found in the case of the block sliding on a frictionless surface. The difference in kinetic energies between the block sliding on a frictionless surface and the block in this example is equal to the increase in internal energy of the block-surface system in this example. (b) Suppose the force F is applied at an angle 8 as shown in figure (b). At what angle should the force be applied to achieve the largest possible speed after the block has moved 2.5 m to the right? SOLUTION Conceptualize You might guess that 0 = 0 would give the largest speed because the force would have the largest component possible in the direction parallel to the surface. Think about F applied at an arbitrary nonzero angle, however. Although the horizontal component of the force would be reduced, the vertical component of the force would -Select- v the normal force, in turn reducing the force of friction, which suggests that the speed could be maximized by pulling at an angle other than 8 = 0. Categorize As in part (a), we model the block and the surface as a nonisolated system with a --Select-- v force acting. Analyze Find the work done by the applied force, noting that d = Ax because the path followed by the block is a straight line (Use the following as necessary: F, Ax, and 0.): (1) 2Wother forces = WE = Fd cos(0) = Apply the particle in equilibrium model to the block in the vertical direction: SF, = n + F sin(6) - mg = o Solve for n (Use the following as necessary: F, Ax, 0, m and g.): (2) n = Use ) Wather forces = W = AK + AEt to find the final kinetic energy for this situation: WE = AK + AEint = (K; - 0) + fAx - K; = WF - fAx Substitute the results in Equations (1) and (2): K; = FAx cos(0) - HnAx = FAx cos(e) – H(mg - F sin(8))Ax Maximizing the speed is equivalent to maximizing the final kinetic energy. Consequently, differentiate K; with respect to 6 and set the result equal to zero (Use the following as necessary: Ax, 0, and g.): = -FAx sin(0) - H(0 - F cos(0))Ax = 0 de -sin(8) + u, cos(0) = 0 Evaluate 6 (in degrees) for u, = 0.14: 0.12 DAA = Hk Evaluate e (in degrees) for 4 = 0.14: e = tan-(u,) = tan-(0.14) = Finalize Notice that the angle at which the speed of the block is a maximum is indeed not 8 = 0. When the angle exceeds 7.97°, the horizontal component of the applied force is too small to be compensated by the reduced friction force and the speed of the block begins to --Select-- v from its maximum value. EXERCISE A 17.5 kg block is dragged over a rough, horizontal surface by a 75 N force acting at 21° above the horizontal. The block is displaced 5.7 m, and the coefficient of kinetic friction is 0.150. (Enter your answers in J.) Hint (a) Find the work done on the block by the 75 N force. (b) Find the work done on the block by the normal force. (c) Find the work done on the block by the gravitational force. (d) What is the increase in internal energy of the block-surface system due to friction? (e) Find the total change in the block's kinetic energy. Need Help? Read It 2. [3.12/3.12 Points] DETAILS PREVIOUS ANSWERS SERPSE10 8.XP.005. MY NOTES ASK YOUR TEACHER An object of mass m starts from rest and slides a distance d down a frictionless incline of angle 0. While sliding, it contacts an unstressed spring of negligible mass as shown in the figure. The object slides an additional distance x as it is brought momentarily to rest by compression of the spring (of force constant k). Find the initial separation d between object and spring. (Use any variable or symbol stated above along with the following as necessary: g.) d = 2mg sin (e) A 4.0 kg block initially at rest is pulled to the right along a horizontal surface by a constant horizontal force of 13 N. (a) A block pulled to the right on a rough surface (b) The applied force is at an angle 8 to the by a constant horizontal force. horizontal. mg mg a (For the following, when entering a mathematical expression, do not substitute numerical values; use variables only.) (a) Find the speed of the block after it has moved 2.5 m if the surfaces in contact have a coefficient of kinetic friction of 0.14. SOLUTION Conceptualize This example is similar to the example "A Block Pulled on a Frictionless Surface" in Chapter 7, but modified so that the surface is no longer frictionless. The rough surface applies a friction force on the block opposite to the applied force. As a result, we expect the speed to be -Select-- v that found in "A Block Pulled on a Frictionless Surface." Categorize The block is pulled by a force and the surface is rough, so the block and the surface are modeled as --Select- v system with a nonconservative force. Analyze Figure (a) illustrates this situation. Neither the normal force nor the gravitational force does work on the system because their points of application are displaced horizontally. Find the work done on the system by the applied force (Use the following as necessary: F and Ax.): > Wother forces = WE = Apply the particle in equilibrium model to the block in the vertical direction (Use the following as necessary: F, Ax, m, and g.): >Fy = 0 + n- mg = 0 -n = Find the magnitude of the friction force (in N): N = buri = ưn = ! Substitute the energies into the equation shown and solve for the final speed of the block (Use the following as necessary: F, Ax and f): FAx = AK + AEint = Gmv? - 0) + fAx FAx = AK + ΔΕint = (mv-0) + fAAx V = Substitute numerical values (Enter your answer in m/s.): m/s Finalize As expected, this value is ---Select-- v that found in the case of the block sliding on a frictionless surface. The difference in kinetic energies between the block sliding on a frictionless surface and the block in this example is equal to the increase in internal energy of the block-surface system in this example. (b) Suppose the force F is applied at an angle 8 as shown in figure (b). At what angle should the force be applied to achieve the largest possible speed after the block has moved 2.5 m to the right? SOLUTION Conceptualize You might guess that 0 = 0 would give the largest speed because the force would have the largest component possible in the direction parallel to the surface. Think about F applied at an arbitrary nonzero angle, however. Although the horizontal component of the force would be reduced, the vertical component of the force would -Select- v the normal force, in turn reducing the force of friction, which suggests that the speed could be maximized by pulling at an angle other than 8 = 0. Categorize As in part (a), we model the block and the surface as a nonisolated system with a --Select-- v force acting. Analyze Find the work done by the applied force, noting that d = Ax because the path followed by the block is a straight line (Use the following as necessary: F, Ax, and 0.): (1) 2Wother forces = WE = Fd cos(0) = Apply the particle in equilibrium model to the block in the vertical direction: SF, = n + F sin(6) - mg = o Solve for n (Use the following as necessary: F, Ax, 0, m and g.): (2) n = Use ) Wather forces = W = AK + AEt to find the final kinetic energy for this situation: WE = AK + AEint = (K; - 0) + fAx - K; = WF - fAx Substitute the results in Equations (1) and (2): K; = FAx cos(0) - HnAx = FAx cos(e) – H(mg - F sin(8))Ax Maximizing the speed is equivalent to maximizing the final kinetic energy. Consequently, differentiate K; with respect to 6 and set the result equal to zero (Use the following as necessary: Ax, 0, and g.): = -FAx sin(0) - H(0 - F cos(0))Ax = 0 de -sin(8) + u, cos(0) = 0 Evaluate 6 (in degrees) for u, = 0.14: 0.12 DAA = Hk Evaluate e (in degrees) for 4 = 0.14: e = tan-(u,) = tan-(0.14) = Finalize Notice that the angle at which the speed of the block is a maximum is indeed not 8 = 0. When the angle exceeds 7.97°, the horizontal component of the applied force is too small to be compensated by the reduced friction force and the speed of the block begins to --Select-- v from its maximum value. EXERCISE A 17.5 kg block is dragged over a rough, horizontal surface by a 75 N force acting at 21° above the horizontal. The block is displaced 5.7 m, and the coefficient of kinetic friction is 0.150. (Enter your answers in J.) Hint (a) Find the work done on the block by the 75 N force. (b) Find the work done on the block by the normal force. (c) Find the work done on the block by the gravitational force. (d) What is the increase in internal energy of the block-surface system due to friction? (e) Find the total change in the block's kinetic energy. Need Help? Read It 2. [3.12/3.12 Points] DETAILS PREVIOUS ANSWERS SERPSE10 8.XP.005. MY NOTES ASK YOUR TEACHER An object of mass m starts from rest and slides a distance d down a frictionless incline of angle 0. While sliding, it contacts an unstressed spring of negligible mass as shown in the figure. The object slides an additional distance x as it is brought momentarily to rest by compression of the spring (of force constant k). Find the initial separation d between object and spring. (Use any variable or symbol stated above along with the following as necessary: g.) d = 2mg sin (e) A 4.0 kg block initially at rest is pulled to the right along a horizontal surface by a constant horizontal force of 13 N. (a) A block pulled to the right on a rough surface (b) The applied force is at an angle 8 to the by a constant horizontal force. horizontal. mg mg a (For the following, when entering a mathematical expression, do not substitute numerical values; use variables only.) (a) Find the speed of the block after it has moved 2.5 m if the surfaces in contact have a coefficient of kinetic friction of 0.14. SOLUTION Conceptualize This example is similar to the example "A Block Pulled on a Frictionless Surface" in Chapter 7, but modified so that the surface is no longer frictionless. The rough surface applies a friction force on the block opposite to the applied force. As a result, we expect the speed to be -Select-- v that found in "A Block Pulled on a Frictionless Surface." Categorize The block is pulled by a force and the surface is rough, so the block and the surface are modeled as --Select- v system with a nonconservative force. Analyze Figure (a) illustrates this situation. Neither the normal force nor the gravitational force does work on the system because their points of application are displaced horizontally. Find the work done on the system by the applied force (Use the following as necessary: F and Ax.): > Wother forces = WE = Apply the particle in equilibrium model to the block in the vertical direction (Use the following as necessary: F, Ax, m, and g.): >Fy = 0 + n- mg = 0 -n = Find the magnitude of the friction force (in N): N = buri = ưn = ! Substitute the energies into the equation shown and solve for the final speed of the block (Use the following as necessary: F, Ax and f): FAx = AK + AEint = Gmv? - 0) + fAx FAx = AK + ΔΕint = (mv-0) + fAAx V = Substitute numerical values (Enter your answer in m/s.): m/s Finalize As expected, this value is ---Select-- v that found in the case of the block sliding on a frictionless surface. The difference in kinetic energies between the block sliding on a frictionless surface and the block in this example is equal to the increase in internal energy of the block-surface system in this example. (b) Suppose the force F is applied at an angle 8 as shown in figure (b). At what angle should the force be applied to achieve the largest possible speed after the block has moved 2.5 m to the right? SOLUTION Conceptualize You might guess that 0 = 0 would give the largest speed because the force would have the largest component possible in the direction parallel to the surface. Think about F applied at an arbitrary nonzero angle, however. Although the horizontal component of the force would be reduced, the vertical component of the force would -Select- v the normal force, in turn reducing the force of friction, which suggests that the speed could be maximized by pulling at an angle other than 8 = 0. Categorize As in part (a), we model the block and the surface as a nonisolated system with a --Select-- v force acting. Analyze Find the work done by the applied force, noting that d = Ax because the path followed by the block is a straight line (Use the following as necessary: F, Ax, and 0.): (1) 2Wother forces = WE = Fd cos(0) = Apply the particle in equilibrium model to the block in the vertical direction: SF, = n + F sin(6) - mg = o Solve for n (Use the following as necessary: F, Ax, 0, m and g.): (2) n = Use ) Wather forces = W = AK + AEt to find the final kinetic energy for this situation: WE = AK + AEint = (K; - 0) + fAx - K; = WF - fAx Substitute the results in Equations (1) and (2): K; = FAx cos(0) - HnAx = FAx cos(e) – H(mg - F sin(8))Ax Maximizing the speed is equivalent to maximizing the final kinetic energy. Consequently, differentiate K; with respect to 6 and set the result equal to zero (Use the following as necessary: Ax, 0, and g.): = -FAx sin(0) - H(0 - F cos(0))Ax = 0 de -sin(8) + u, cos(0) = 0 Evaluate 6 (in degrees) for u, = 0.14: 0.12 DAA = Hk Evaluate e (in degrees) for 4 = 0.14: e = tan-(u,) = tan-(0.14) = Finalize Notice that the angle at which the speed of the block is a maximum is indeed not 8 = 0. When the angle exceeds 7.97°, the horizontal component of the applied force is too small to be compensated by the reduced friction force and the speed of the block begins to --Select-- v from its maximum value. EXERCISE A 17.5 kg block is dragged over a rough, horizontal surface by a 75 N force acting at 21° above the horizontal. The block is displaced 5.7 m, and the coefficient of kinetic friction is 0.150. (Enter your answers in J.) Hint (a) Find the work done on the block by the 75 N force. (b) Find the work done on the block by the normal force. (c) Find the work done on the block by the gravitational force. (d) What is the increase in internal energy of the block-surface system due to friction? (e) Find the total change in the block's kinetic energy. Need Help? Read It 2. [3.12/3.12 Points] DETAILS PREVIOUS ANSWERS SERPSE10 8.XP.005. MY NOTES ASK YOUR TEACHER An object of mass m starts from rest and slides a distance d down a frictionless incline of angle 0. While sliding, it contacts an unstressed spring of negligible mass as shown in the figure. The object slides an additional distance x as it is brought momentarily to rest by compression of the spring (of force constant k). Find the initial separation d between object and spring. (Use any variable or symbol stated above along with the following as necessary: g.) d = 2mg sin (e)
Expert Answer:
Related Book For
College Physics Reasoning and Relationships
ISBN: 978-0840058195
2nd edition
Authors: Nicholas Giordano
Posted Date:
Students also viewed these physics questions
-
A 1.50-m-Iong metal bar is pulled to the right at a steady 5.0 m/s perpendicular to a uniform, 0.750-T magnetic field. The bar rides on parallel metal rails connected through a 25.0-n resistor, as...
-
In Figure, three connected blocks are pulled to the right on a horizontal frictionless table by a force of magnitude T3 = 65.0 N. If m1 = 12.0kg, m2 = 24.0 kg, and m3 = 31.0 kg, calculate (a) The...
-
A block on a spring is pulled to the right and released at t = 0 s. It passes x = 3.00 cm at t = 0.685 s, and it passes x = -3.00 cm at t = 0.886 s. a. What is the angular frequency? b. What is the...
-
Solve the equation (a) Graphically, (b) Numerically, and (c) Symbolically. Then solve the related inequality. |4x7| = 5, |4x - 7| 5
-
Should individuals have the right to sue for damages for the purchase of a product that is less than $25.00 in value? What harm has Mr. Bass really suffered?
-
Tyler Tooling Company uses a job order cost system with overhead applied to products on the basis of machine hours. For the upcoming year, the company estimated its total manufacturing overhead cost...
-
A company wishes to hedge its exposure to a new fuel whose price changes have a 0.6 correlation with gasoline futures price changes. The company will lose $1 million for each 1 cent increase in the...
-
Context-sensitive nature of cost behavior classifications Susan Hicks operates a sales booth in computer software trade shows, selling an accounting software package, Dollar System. She purchases the...
-
This table lists the gross property tax distribution applicable to a local homeowner. Property Tax Distribution. Taxing Authority 2017 2018 Airport $45.88 $46.71 Citilink - PTC $63.69 $66.18 City...
-
The Kentucky Derby is held the first Saturday in May at Churchill Downs in Louisville, Kentucky. The race track is one and one-quarter miles. The following table shows the winners since 2000, their...
-
On December 31, 2020 Lamentable Company had the following cash balances: Cash in bank-current account Petty cash fund-all funds were reimbursed at year-end Time deposit-three months, due January 15,...
-
Discuss practical approaches for effective team management and leadership What is an organisational vision and goal? What are organisation's visions and goals? How do visions and goals apply to an...
-
You have been hired by up and coming company Gekko & Co. to create a pay stub calculator for their employees. Their employees are paid only once per month. The pay stub will show take-home pay for...
-
A ball rolls off the edge of A 1.0 m high table with a horizontal speed of 2.0 m/s. How far from the base of the table will the ball land?
-
Predict the output of the following program? Assuming test.txt file exists in C drive( C://test.txt) import java.io.*; class Test } public static void main(String args[]) throws IOException { }...
-
2. Given an analog signal has a range of -4V to 4V, an Analog to Digital Convertor (ADC) will sample the signal every 10ms and map this signal to a digital range from 0 to 8. a. Draw an analog signal...
-
5) Derek's Donuts is considering two mutually exclusive investments. The projects' expected net cash flows are as follows: Year 0 1 2 3 4 5 6 7 Project K S(300) (387) (193) (100) 500 500 850 100 If...
-
The Smiths buy a house. They borrow 80 percent of the purchase price from the local ABC Savings and Loan. Before they make their first payment, ABC transfers the right to receive mortgage payments to...
-
Two balls of the same diameter are dropped simultaneously from a very tall bridge. One ball is solid lead, and the other is hollow plastic and has a much smaller mass than the solid lead ball. Use a...
-
Consider two inductors L 1 and L 2 connected in parallel as shown in Figure P21.45. These two inductors act as one equivalent inductance L equiv . To find L equiv , we first notice that because they...
-
Consider again the wedge in Question 6, but now assume a block is placed onto it as shown in Figure Q4.7. There is again no friction between the wedge and the table, and there is also no friction...
-
Bethany, who weighs 560 N, lies in a hammock suspended by ropes tied to two trees. One rope makes an angle of 45 with the ground; the other makes an angle of 30. Find the tension in each of the ropes.
-
In the Skycoaster amusement park ride, riders are suspended from a tower by a long cable. A second cable then lifts them until they reach the starting position indicated in Figure P5.3. The lifting...
-
In the winter sport of curling, two teams alternate sliding 20 kg stones on an icy surface in an attempt to end up with the stone closest to the center of a target painted on the ice. During one...
Study smarter with the SolutionInn App