C++ code please

Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal". Hint: Use epsilon value 0.0001. Ex: If targetValue is 0.3333 and sensorReading is (1.0/3.0), output is: Equal Code writing challenge activity demo 448478.3062798.qx3zqy7 567891011121314151617181920 int main() { double targetValue; double sensorReading; cin >> targetValue; cin >> sensorReading; if (/* Your solution goes here */) { cout << "Equal" << endl; } else { cout << "Not equal" << endl; } return 0;}