Question: In C Write an expression that will cause the following code to print Equal if the value of sensorReading is close enough to targetValue. Otherwise,

In C
Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal". Hint: Use epsilon value 0.0001. Ex: If targetValue is 0.3333 and sensorReading is (1.0/3.0), output is: Equal Code writing challenge activity demo 5678910111213141516171819doubletargetValue;doublesensorReading;scanf("%lf",&targetValue);scanf("%lf",&sensorReading);if(Yoursolutiongoeshere*{printf("Equal );}else{printf("Notequal ");}return0
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