ANSWER IN C LANGUAGE: Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to targetValue. Otherwise, print "Not equal". Hint: Use epsilon value 0.0001. Ex: If targetValue is 0.3333 and sensorReading is (1.0/3.0), output is:

Equal

#include #include

int main(void) { double targetValue; double sensorReading;

scanf("%lf", &targetValue); scanf("%lf", &sensorReading);

if (/* Your solution goes here */) { printf("Equal "); } else { printf("Not equal "); }

return 0; }