Write an expression that will cause the following code to print "Equal" if the value of sensorReading is "close enough" to

targetValue Otherwise, print "Not equal". Hint: Use epsilon value $0\mathrm{.}0001.$ Ex: If targetValue is $0\mathrm{.}3333$ and sensorReading is

$(\frac{1\mathrm{.}0}{3\mathrm{.}0}),$ output is:

Equal

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doub le sensorkeadingNumerator;

double sensorReadingDenominator;

double sensorReading;

scanf$("6$ lf$",$ &targetValue$)$;

scanf$("$ var${}_{}lf",$ &sensorReadingNumerator$)$;

scanf$("\%$lf$",$ &sensorReadingDenominator$)$;

sensorReading $=$ sensorReadingNumerator $/$ sensorReadingDenominator;

if $($sensorReading $=0\mathrm{.}0001($

$\}$

printf$("$Equalin$")$;

else $\{$

$\}$

printf$("$Not equal$$n$")$;

$$ Not all tests passed

Testing with targetValue $=0\mathrm{.}3333,$ sensorReading $=\frac{1\mathrm{.}0}{3},0$