can someone fix this please

Question 6 (45 points). Consider the following data for a project to install a new server at the Northland Pines High School: Immediate Predecessor(8) Activity Activity Time (days) 2 B 4 A I S A D 2 B E 1 B F 8 B,C DE G 3 H 5 F 1 4 F J G, HI 7 a) Draw the network diagram. b) Calculate the critical path for this project. ) How much slack is in each activity? Edge and it's preceded and succeeded node Edge Nodel Node2 A 1-2 B 2-3 a) Draw the network diagram. b) Calculate the critical path for this project. c) How much slack is in each activity? Edge and it's preceded and succeeded node Edge Nodel Node 2 A 12 B 2-3 2-4 d 3-4 D 3-5 E 3-6 F 47 d 5-6 G 68 H 7-8 1 79 d 8+9 J 9-10 The network diagram for the project, along with activity time, is D(2) 5 B(4) 3 3 d(0) G(3) 1 A(2) 2 d(0) E(16 8 H(5) C(5) 4 F(8) 7 d(0) (4) 9 J(7) 10 Forward Pass Method E1-0 E2-E1+1 2 [t1,2-A-2] 0+2-2 Forward Pass Method E1-0 E2=E1+1,2 [t1,2=A-2] 0+2=2 E3-E2+2,3 [12,3-B-4)=2+4-6 E4=Max{Ei+ti,4}[i=2,3] =Max {E2+12,4;E3+13,4} =Max {2+5;6+0) =Max {7;6) ES-E3+13,5 (13,5-D-2]-6+2-8 E6 Max {Eitti,6}[i-3,5) -Max (E3+13,6;ESH15,6) -Max {6+1;8+03 =Max{7;8) =8 E7=E4+14,7 (+4,7=F=8)=7+8=15 E8-Max {Ei+ti,8}[i=6,7] =Max {E6+t6,8;E7+17,8) =Max {8+3;15+5) =Max{11:20) = 20 E9-Max {Eitti,9][i-7,8] =Max {E7+17,9;E8+18,9) =Max {15+4:20+03 =Max{19:20) =20 E10-E9+19,10 [19.10-J-7]-20+7-27 Backward Pass Method L10-10-27 L9 L10-19,10 [19,10-) 7)-27-7-20 L8-L9-18,9 (18,9d-0-20-0-20 L7=Min{Lj-17.j}(i=9,81 =Min{L9-47,9;L8-17,8) =Min{20-4:20-5) =Min{16;15) =15 L6=L8-16,8 (16,8-G=3)=20-3=17 L5 L6-15,6 [15,6-d0]=17-0=17 L4=L7-14,7 14,7=F-8)=15-8=7 L3=Min{Lj-t3.j} (-6,5,4] =Min{L6-13,6;L5-13,5:L4-13,4) =Min (17-1:17-2:7-03 Min{16;15:7) L2-Min{Lj-2.j} [=4,3] =Min{L4-12,4;L3-12,3) =Min (7-5-7-43 =Min (2:3) =2 L1=L2-1,2 [t1,2=A-23-2-2-0 (b) The critical path in the network diagram has been shown. This has been done by double lines by joining all those events where E-values and L-values are equal The critical path of the project is : 1-2-4-7-8-9-10 and critical activities are ACEH,,, The total project time is 27 The network diagram for the project, along with E-values and L-values.is ES 5 Ez 6 D(2) L - 7 E-8 3 Ko-17 -8 Its - 17 E8-201 K8 - 20 B(4) 3 d(0) G(3) 1 A(2) 2 d(0) E(1) 6 8 E22 E10-27 E-0 21 0 C(5) 4 F(8) H(5) E, -20 7 K-201 FM 15 L (4) 15 alo 110 27 E = 7 LA = 7 . 2 9 J(7) 10 (c) For each non-critical activity, the total float, free float and independent float calculations are shown in Table Earliest Activity Duration time (tij) Start (1) (2) (EI) (3) Latest Earliest Latest time time time Total Free Independent (EJ) (LI) Finish Finish Start Float Float Float (4) (5) (LD) (Ei+tij) (4-tip) (L (Ej (EJ-LI)-tij (6) (7) (8) tij) EI) (11)=((4)- (3)+(2) (6)-(2) EI tij (5))-(2) (9) (10) (8)- (3) (3))- (2) 2-3 4 2 6 2 7 6 3 1 0 Oo 3-4 0 6 7 7 7 6 7 1 1 3-5 2 6 8 7 17 8 15 9 o 3-6 1 6 8 7 17 7 16 10 1 o 5-6 0 8 8 17 17 8 17 9 O -9 6-8 3 8 20 17 20 11 17 9 9 0 7.9 4 15 20 15 20 19 16 1 1 1 For problem 6, your diagram should include the activities in the nodes. You put the activities to the arcs, which makes it wrong. The arcs are connectors, the activities should be in the circle nodes. Your start time, end time and slack computations are not correct. I cannot understand which activity is in each row when I look at your table in part c. For example, is the first activity 2-3 activity A? There is no information on that. I suggest you review the practice question videos to redo this