Computers can use basic logic operations to selectively manipulate certain bits in one or more bytes...

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Computers can use basic logic operations to selectively manipulate certain bits in one or more bytes of data. This is referred to as masking. Suppose you have an 8-bit binary number (referred to as "X"). You are going to perform the same logic operation (AND, OR, NAND, or NOR) on each bit in the binary number. You will use another 8-bit binary number (referred to as "M") in the operation since most logic operations involve two inputs. The final result from the operation should be an 8-bit binary number where the first and last bits are 0, and the middle six bits will be the same as they are in X. For example: operation X7 M7 X7 0 0 X6 X5 X4 M6 M5 M4 What logic operation must you use to accomplish this goal? Choose from AND, OR, NAND, NOR X6 X6 X5 What must the 8-bits of M be in order to accomplish this goal? Note that each bit of M must be permanently set to either 0 or 1 and cannot be dependent on any of the bits in X, since you don't know what the X values are. Enter the values of the 8-bits of Min the boxes below: X6 X5 X3 X2 X1 Xo M3 M₂ M₁ Mo X4 X3 X2 X₁ 0 X5 X4 X4 X3 X₂ X3 X₁1 Xo X₂ X₁ 0 Computers can use basic logic operations to selectively manipulate certain bits in one or more bytes of data. This is referred to as masking. Suppose you have an 8-bit binary number (referred to as "X"). You are going to perform the same logic operation (AND, OR, NAND, or NOR) on each bit in the binary number. You will use another 8-bit binary number (referred to as "M") in the operation since most logic operations involve two inputs. The final result from the operation should be an 8-bit binary number where the first and last bits are 0, and the middle six bits will be the same as they are in X. For example: operation X7 M7 X7 0 0 X6 X5 X4 M6 M5 M4 What logic operation must you use to accomplish this goal? Choose from AND, OR, NAND, NOR X6 X6 X5 What must the 8-bits of M be in order to accomplish this goal? Note that each bit of M must be permanently set to either 0 or 1 and cannot be dependent on any of the bits in X, since you don't know what the X values are. Enter the values of the 8-bits of Min the boxes below: X6 X5 X3 X2 X1 Xo M3 M₂ M₁ Mo X4 X3 X2 X₁ 0 X5 X4 X4 X3 X₂ X3 X₁1 Xo X₂ X₁ 0

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The logic operation required to achieve the goal outlined in the questionto make the first ... View the full answer